Ap=8,3,-2.........find Sn

1.	Ap=8,3,-2.........find Sn
Answer» Here {tex}a = 8,\\ d = 3 - 8 = -5.{/tex}So, Sn\xa0= {tex}\\frac{n}{2}{/tex}[2a + (n\xa0- 1)d]{tex}\\Rightarrow{/tex}\xa0{tex}S_{n}\xa0= \\frac n2(16 - 5n + 15) = \\frac n2(31 - 5n){/tex}

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