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Ap is 27,23,19.....-65 find its 11th term from last |
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Answer» A=27, d=23-27=-4, An=-65An=A+(n-1)d-65=27+(n-1)(-4)-65=27-4n+4-65=31-4n-65-31=-4n-96=-4n96=4n96/4=n24=nAfter thatto find last 11th term, we have to sub24-10=14it means we to find the 14th termNow, 14th term=a+13d =27+13(-4) =27-52 =-25 -25 To solve this we will form the AP in reverse orderSo, a=-65 d=4a11=a+10da11=-65+40=-25 |
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