At a metro station, a girl walks up a stationary escalator in time `t_1` If she remains stationary on the escalator, then the escalator take her up in time `t_2`. The time taken by her to walk up the moving escalator will be.A. `(t_1 + t_2)//(2)`B. `t_1 t_2//(t_2 - t_1)`C. `t_1 t_2//(t_2 + t_1)`D. `t_1 - t_2`

At a metro station, a girl walks up a stationary escalator in time `t_

1.	At a metro station, a girl walks up a stationary escalator in time `t_1` If she remains stationary on the escalator, then the escalator take her up in time `t_2`. The time taken by her to walk up the moving escalator will be.A. `(t_1 + t_2)//(2)`B. `t_1 t_2//(t_2 - t_1)`C. `t_1 t_2//(t_2 + t_1)`D. `t_1 - t_2`
Answer» Correct Answer - C We have to find net velocity with respect to the Earth that will be equal to velocity o fthe girl plus velocity of escalator. Let dispalcemet is `L`, then Velocity of girl `v_g = (L)/(t_1)` Velocity of escalator `v_e = (L)/(t_2)` Net velocity of the girl `=v_g + v_e = (L)/(t_1)+(L)/(t_2)` It `t` is total time taken is covering distance `L`, then `(L)/(t) = (L)/(t_1)+(L)/(t_2) rArr t = (t_ 1 t_2)/(t_1 + t_2)`.

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