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At the expense of two ATP molecules, how many phosphate groups are present on the fructose in the third step of glycolysis?(a) 2(b) 3(c) 4(d) 5This question was addressed to me in examination.Question is from Aerobic Respiration topic in division Nucleus & Aerobic Respiration of Cell Biology

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Correct CHOICE is (a) 2

To explain I would say: Glucose is FIRST phosphorylated at the expense of one ATP molecule, rearranging to form FRUCTOSE phosphate and then PHOSPHORYLATION takes place again LEADING to a total of two phosphate groups attached to the fructose chain.



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