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ax+by=(a-b)bx-ay=(a+b)This question of pair of linear equation in two variable...plz solve it |
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Answer» Thnku.. Given,\xa0ax + by = a - b .......1 bx - ay = a + b .......2Multiply by a in equation 1 and b in equation 2, we geta2 x + aby =\xa0a2 - ab .......3 b2 x - aby = ab + b2 .......4Add equation 3 and 4, we get a2\xa0x + aby +\xa0b2\xa0x - aby =\xa0a2\xa0- ab +\xa0ab + b2=>\xa0a2\xa0x +\xa0b2\xa0x =\xa0a2\xa0+ b2\xa0=> x(a2\xa0+\xa0b2\xa0) =\xa0a2\xa0+ b2=> x =\xa0(a2\xa0+\xa0b2\xa0)/(a2\xa0+\xa0b2\xa0)\xa0=> x = 1Put value of x in equation 1, we get=>\xa0a + by = a - b=>\xa0by = a - b - a=> by = -b=> y = -b/b=> y = -1So, x = 1, y = -1 |
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