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Calculate the no of electron constituting 1 Columb charge |
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Answer» We know that 1electron contain s -1.6×10^19 coulomb. e=1.6 ×10^19 C. So let charge=q. Let no.of electrons=n. Charge of 1 electron=e. We known that q=ne. n=q/e. -1st equation. Substituting values in eq.1st we get. 1/(-1.6 ×10^19) = 6.25 × 10^18 electrons Q=ne therefore n=q/e and n=1 C/1.6×10^-19 So, n=6.25 ×10^18 |
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