1.

Calculate the number of neutrons emitted when `._(92)U^(235)` undergoes controlled nuclear fission to `._(54)Xe^(142) ` and `._(38)Sr^(90)`.

Answer» `._(92)U^(235)rarr._(54)Xe^(142)+._(38)Sr^(90)=x._(0)n^(1)`
Equating atomic number on both sides
`235=142+90+x` ltbr. `:. X=3`
Hence, 3 neutrons are emitted.


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