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Calculate the number of neutrons emitted when `._(92)U^(235)` undergoes controlled nuclear fission to `._(54)Xe^(142) ` and `._(38)Sr^(90)`. |
Answer» `._(92)U^(235)rarr._(54)Xe^(142)+._(38)Sr^(90)=x._(0)n^(1)` Equating atomic number on both sides `235=142+90+x` ltbr. `:. X=3` Hence, 3 neutrons are emitted. |
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