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The half of `""_(92)""^(238)U` against `alpha`-decay is `4.5xx10""^(9)`year. The time taken in year for the decay of `15/16` part of the isotope isA. `9.0xx10""^(9)`B. `1.8xx10""^(10)`C. `4.5xx10""^(9)`D. `2.7xx10""^(10)` |
Answer» Correct Answer - b `N=N""_(0)/2""^(n)(n=t//t""_(1//2))` |
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