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Uranium (`""_(92)U""^(238)`) decayed to `""_(82)Pb""^(206)`. The process is `""_(92)U""^(238)underset(xalpha,ybeta)to.""_(82)Pb""^(206)` `t""_(1//2)of U""^(238)=4.5xx10""^(9)` years x and y in above decay series areA. 6.8B. 9.6C. 8.8D. 8.6 |
Answer» Correct Answer - d `alpha=(Ap-Ad)/4,beta=2xxalpha-(Zp-Zd)` |
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