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In the nuclear reaction `._(92)U^(238) rarr ._(82)Pb^(206)`, the number of alpha and beta particles decayed areA. `4 alpha, 3 beta`B. `8 alpha, 6 beta`C. `6 alpha, 4 beta`D. `7 alpha, 5 beta` |
Answer» Correct Answer - B Number of `alpha`- particles `= (238 - 206)/(4) = 8` Number of `beta`- particles `= 2xx 8 - 92 + 82 = 6` |
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