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Uranium `._(92)U^(238)` decayed to `._(82)Pb^(206)`. They decay process is `._(92)U^(238) underset((x alpha, y beta))(rarr ._(82)Pb^(206))` `t_(1//2)` of `U^(238) = 4.5 xx 10^(9)` years Atomic mass of `U^(238)` is 238.125 amu. Its packing fraction will beA. 6.25B. 0.125C. 12.5D. 5.25

Answer» Correct Answer - d
`t=(2.303xxt""_(1//2))/0.693log.(1+(pb""^(206))/U""^(238))`


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