Calculate the positions of the principle planes and focal points of a thick convex-concave glass lens if the curvature radius of the convex surface is equal to `R_(1) = 10.0 cm` and of the concave surface to `R_(2) = 5.0 cm` and the lens thickness is `d = 3.0 cm`.

Calculate the positions of the principle planes and focal points of a

1.	Calculate the positions of the principle planes and focal points of a thick convex-concave glass lens if the curvature radius of the convex surface is equal to `R_(1) = 10.0 cm` and of the concave surface to `R_(2) = 5.0 cm` and the lens thickness is `d = 3.0 cm`.
Answer» The optical power of first convex surface is, `Phi = (P(n - 1))/(R_(1)) = 5D`, as `R_(1) = 10 cm` and the optical power of second concave surface is, `Phi_(2) = ((1 - n))/(R_(2)) =- 10D` So, the optical power of the system, `Phi = Phi_(1) + Phi_(2) -(d)/(n)Phi_(2) =-4D` Now, the distance of the primary principle plane from the vertex surface is given as, `x = ((1)/(Phi))((d)/(n)) Phi_(2)`, here `n_(1) = 1` and `n_(2) = n`. `= (d Phi_(2))/(Phin) = 5cm` and the distance of secondary principle plane from the vertex of second concave surface, `x =-((1)/(Phi))((d)/(n)) Phi_(1) =- (d Phi_(1))/(Phi n) = 2.5 cm`

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Calculate the positions of the principle planes and focal points of a thick convex-concave glass lens if the curvature radius of the convex surface is equal to `R_(1) = 10.0 cm` and of the concave surface to `R_(2) = 5.0 cm` and the lens thickness is `d = 3.0 cm`.

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