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Calculate the resolving power of a microscope if its numerical aperture is `0.12` and wavelength of light used is `6000 Å`. |
Answer» Here, `N.A. = mu sin theta = 0.12`, `lambda = 6000 Å = 6 xx 10^(-7) m` R.P. of microscope, `(1)/(d) = (2 mu sin theta)/(lambda) = (2 xx 0.12)/(6 xx 10^(-7)) = 4 xx 10^(5) m^(-1)` |
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