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Calculate the speed of light in a medium whose critical angle is `45^(@)`. |
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Answer» Correct Answer - `2.12 xx 10^(8) m//s` Here, `v = ?, C = 45^(@)` `mu = (1)/(sin C) = (1)/(45^(@)) = sqrt(2)` `v = ( c)/(mu) = (3 xx 10^(8)m//s)/(sqrt(2)) = 2.12 xx 10^(8)m//s` |
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