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| 1. |
Can anyone explain the 1st question of 3rd section from exercise 1.3 |
| Answer» \xa0(i)\xa0We can prove\xa0irrational by contradiction.Let us suppose that\xa0\xa0is rational.It means we have some co-prime integers\xa0a\xa0and\xa0b\xa0(b\xa0≠ 0) such that=ab⇒\xa0\xa0…\xa0(1)R.H.S\xa0of\xa0(1)\xa0is rational but we know that\xa0\xa0is irrational.It is not possible which means our supposition is wrong.Therefore,\xa0\xa0cannot be rational.Hence, it is irrational. | |