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Can anyone prove that sum of any 3 consecutive natural no is divisible by6 |
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Answer» No I was just kidding Hey priyanshi shayad aap chatting kar rhi h... ??? Isse acha to aap kisi or lrdki ko de dete... Km se km back to nhi lena prta Bechara ayush..... Yeah it was one of the easiest Then i take all my kisses back ?? Muje lga tha ki aap girl ho... Sry... U r boy??? In short Let no be x , x+1 , x+2 !! Now sum of these three = x+x+1+x+2 = 3x+3 = 3(x+1) !! By euclid. Lemma ...it is in form.of bq +r where r is 0 . it is divisible by 3 Yes so easy It\'s not a proof you have to prove it theoretically It is 6 divisible by 3 1+2+3 Sorry no 6 its3 |
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