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Can anyone solve this for me ..(1+tan^2A/1+cot^2A)=(1-tan A)^2/(1-cot A)^2=tan^2A

Answer» {tex}1+tan^2A/ 1+cot^2A{/tex}{tex}Sec^2A/Cosec^2A{/tex}1/cos2A .Sin2A/1Sin2A/Cos2ATan2A


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