Can the numbet 6,n bring a natural number end with the digitb 5 give r

1.	Can the numbet 6,n bring a natural number end with the digitb 5 give reason
Answer» If 6n\xa0ends with 0 or 5 then it must have 5 as a factor.Now 6n\xa0=\xa0{tex}( 2 \\times 3 ) ^ { n } = 2 ^ { n } \\times 3 ^ { n }{/tex}The prime factors of 6n are only 2 and 3And from the fundamental theorem of arithmetic, the prime factorization of every composite number is unique.{tex}\\therefore{/tex}\xa06n\xa0can never end with 0 or 5.

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