Saved Bookmarks
| 1. |
Ch6 ex.6.4 ques.7 |
| Answer» We know that area of an equilateral triangle with side a={tex}\\sqrt3{/tex} a2/4now let side of square =xthen area of equilateral triangle on one sideA1={tex}\\sqrt3{/tex}\xa0x2/4--------------------------(1)If length of diagonal is d thend2=x2+x2=2x2area of equilateral traingle at diagonalA2=={tex}\\sqrt3{/tex}\xa0*2x2/4=2*({tex}\\sqrt3{/tex} a2/4)=2A1hence proved\xa0 | |