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Chapter 6.2 question no. 9 can someone solve it for me |
| Answer» Draw the figure with the help of hints given belowGiven: ABCD is a trapezium and ABllDCConstruction: draw a line EO such that DCllEOllABTo prove: AO/BO=CO/DOProof: In triangle ADC DE/EA=AO/CO (By B.P.T.) Consider it as equation 1 In triangle ADB DE/EA= BO/DO (ByB.P.T.) Consider it as equation 2 From equation 1 and 2 we get AO/CO= BO/DO = AO/BO=CO/DO (By alternendo) Hence, proved | |