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Check whether the following is a equation or not. (x²+1)(x+1)= (x+3)² |
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Answer» X(x²+1)+1(x²+1)=||+X³+X+x²+1=(x+3)²=||As it is=x²+3³+2(x)(3)=|| ""=X²+9+6xX³+X+x²+1==X²+9+6x{x² cancel by x²}__{+1-9=-8}_{x-6x=-5x}Then the left equation will beX³-5x-8=0And degree of equations is highest power of equationsAnd here the highest power is 3 ,so it is cubic equations not quadratic equations No, because xcube -5x -8 |
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