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Class tenth maths ex 6.4 question no 3 |
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Answer» To prove: ar(ABC)/ar(DBC) =OA/ ODFirst of all we have to do construction.Draw two perpendiculars AP& DM on BcProof : In ∆ ABC & ∆ DCBArea of ∆ Abc÷Area of∆ Dcb= 1/2 × BC×AP÷1/2 × BC × DMArea of∆ Abc/ Area of∆ Dcb= AP/DM.......(1)Now, In ∆Aop & ∆ DomAngle p = Angle M( due to 90°)angle Aop= angle Dom( V.O.A) ∆ AOP~ ∆ DOM( A.A criteria)Ap/ DM= OP/ OM = AO/DOAP/DM= AO/DO....(2)So from 1 & 2 we can say thatar(ABC)/ar(DBC)= OA/DOI hope that it will help you! It\'s too easy Yes I know |
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