1.

Consider a circuit having resistances 2 Ω and 2 Ω in series with an inductor of inductance 2 H. The circuit is excited by a voltage of 12 V. A switch S is placed across the first resistance. Battery has remained switched on for a long time. The current i(t) after switch is closed at t=0 is _____________(a) 6(b) 6 – 3e^-t(c) 6 + 3e^-t(d) 3 – 6e^-tThe question was asked in an online interview.The doubt is from Advanced Problems on Network Theory topic in division Network Theory and Complex Circuit Diagram of Network Theory

Answer»

The correct CHOICE is (B) 6 – 3e^-t

The EXPLANATION is: From the figure, we can infer that,

I(t) = \(\frac{12}{12} \left(1 – \frac{2}{4}e^{-t}\right)\)

= 6 – 3e^-t.



Discussion

No Comment Found

Related InterviewSolutions