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Consider a dyhybrid cross of AaBb with AaBb, how many of the offsprings will breed true?(a) 1/16(b) 2/16(c) 6/16(d) 4/16I have been asked this question in quiz.The above asked question is from Numerical Problems topic in section Mendelian Genetics of Cytogenetics

Answer»

The correct option is (d) 4/16

The explanation: In this CASE, all of AA BB, AA bb, aa BB and aa bb will breed true. This MAKES 4 out of 16 being true breeding. In a PUNETT square these are along the DIAGONALS.



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