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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

________________ aneuploidy is better tolerated.(a) Nullisomic(b) Autosomal(c) Sex chromosomal(d) Chromosome 13I had been asked this question in unit test.Query is from Chromosomal Abnormalities : Aneuploidy in section Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Correct option is (c) Sex chromosomal

The explanation is: In case of sex chromosome due to dosage compensation in FEMALE ONE of X chromosome is INACTIVATED. This is similar to the ABSENCE of a sex chromosome, which makes sex chromosome ANEUPLOIDY less lethal.

2.

In an experiment, you culture the anthers and leaves of a flower. You see the plants so generated are_____________(a) Triploid(b) Monoploid and diploid(c) Diploid and triploid(d) DiploidThis question was posed to me in unit test.Question is from Chromosomal Abnormalities : Euploidy in portion Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Correct option is (b) MONOPLOID and DIPLOID

The explanation: Anthers are the meiosis products, so the plant GENERATED from it is monoploid. Leaf is a normal diploid SOMATIC TISSUE which will give to diploid individual.

3.

Deletion in sex chromosome is better tolerated than that in autosome.(a) True(b) FalseI had been asked this question in homework.This interesting question is from Chromosomal Abnormalities : Deletion in portion Chromosomal Basis of Inheritance of Cytogenetics

Answer»

The correct choice is (a) True

To EXPLAIN: There are GREATER possibilities of SURVIVAL with deletion of GENES in sex chromosome, than that in case of autosomal deletion.

4.

The Streisinger’s model explains__________(a) Frame shifts(b) Transposition(c) Inversion(d) TransitionThe question was asked during an interview.My question is from Chromosomal Abnormalities : Duplication in division Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Correct answer is (a) Frame shifts

Explanation: Streisinger’s model explains that the Frame SHIFT MUTATIONS are more frequent in REPETITIVE SEQUENCES. This causes DUPLICATIVE insertion and also at times deletion.

5.

In an experiment you develop immune response in mice against salmonella flagellar antigen. However, you observe the infection still persisted. Which if a likely possibility if immune system is functioning properly?(a) Salmonella shed its flagella(b) The antigen lost its specificity gradually(c) The flagella antigen changed(d) Infection was not due to salmonellaI got this question by my school teacher while I was bunking the class.Question is from Chromosomal Abnormalities : Translocation topic in section Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Correct answer is (c) The flagella antigen changed

Easy explanation: In SALMONELLA, the flagellar antigen is target for immune RESPONSE. His antigen’s phase can VARY with presence of insertion sequence WITHIN the gene. In this case change of antigen could lead to a loss of SPECIFICITY by the immune system.

6.

What percentage of the human genome is transposition related?(a) 2%(b) 10%(c) 50%(d) 80%The question was posed to me during an online interview.This interesting question is from Chromosomal Abnormalities : Translocation in chapter Chromosomal Basis of Inheritance of Cytogenetics

Answer» RIGHT choice is (c) 50%

The explanation is: 50% of the human and maize genetic elements in involved in transposition. This is a HUGE amount and shows the evolutionary IMPORTANCE of transposition.
7.

Choose the wrong option.(a) Paracentric inversion cross over products is non-viable(b) Pacentric non-cross over gametes segregates normally(c) Double cross over in paracentric inversion is lethal(d) There is genetic imbalance in gametes produced by paracentric inversion cross overI got this question in an online interview.Question is from Chromosomal Abnormality : Inversion in section Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Right OPTION is (C) DOUBLE cross over in paracentric inversion is lethal

For EXPLANATION: In paracentric inversion there is chromosomal imbalance in products of SINGLE cross over, but double cross over products lead to normal gene balance and viable gametes.

8.

Choose the wrong option.(a) Transposons have trasposase along with other genes(b) Transposons lack inverted terminal repeats(c) Transposons have insertion sequences within it(d) Class III transposons are called MITESI had been asked this question in a national level competition.My doubt is from Chromosomal Abnormalities : Translocation topic in division Chromosomal Basis of Inheritance of Cytogenetics

Answer» RIGHT ANSWER is (b) Transposons lack inverted terminal repeats

Explanation: Transposons have Inverted Terminal Repeats, further they may have two INSERTION sequences at two ends. They have many GENES which often include antibiotic resistance gene.
9.

If there are two sequences CGCGCGCG and ATATATAT, which will have a higher probability of being duplicated?(a) ATATATATAT(b) CGCGCGCGCG(c) Both will have equal probability(d) Both are unlikely to be duplicatedI got this question in quiz.I would like to ask this question from Chromosomal Abnormalities : Duplication topic in division Chromosomal Basis of Inheritance of Cytogenetics

Answer»

The correct choice is (c) Both will have equal probability

The explanation is: Streisinger model WORKS on REPEATED SEQUENCES, it is not BASE specific. In this case both the AT rich and CG rich sequences should have an equal probability of getting DUPLICATED.

10.

Which of the following transpose using RNA intermediate?(a) Class I transposon(b) Class II transposon(c) Class III transposon(d) Class IV transposonI have been asked this question at a job interview.This is a very interesting question from Chromosomal Abnormalities : Translocation in section Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Correct answer is (a) Class I TRANSPOSON

For explanation: Class I transpose or retro TRANSPOSONS are those that 1^st TRANSCRIBE the transposon DNA to RNA, then USING reverse transcriptase enzyme they insert the sequence within the recipient DNA.

11.

The chromosomal theory of inheritance violates which of the following laws?(a) Law of dominance(b) Law of segregation(c) Law of independent assortment(d) NoneI got this question during a job interview.I want to ask this question from Chromosomal Theory of Inheritance topic in chapter Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Right option is (d) None

Easy explanation: The chromosomal THEORY of inheritance VIOLATED none of MENDEL’s laws as the only DIFFERENCE was the genes being present in the CHROMOSOME, other than that the laws are as they were.

12.

Extreme klinefelter is an example of _____________________(a) Monosomy(b) Trisomy(c) Disomy(d) TetrasomyThis question was posed to me in a job interview.The query is from Chromosomal Abnormalities : Aneuploidy in section Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Right choice is (d) Tetrasomy

The best explanation: In extreme klinefelter the chromosomal constitution is 44+XXXY, there are TWO extra X CHROMOSOMES which LEADS to more severe Klinefelter condition. THUS, it is tetrasomy.

13.

Sexual mosaics lead to formation of _______________(a) Female from male egg(b) Gynandromorph(c) Klinefelter(d) TrisomyI have been asked this question in a national level competition.My doubt stems from Chromosomal Abnormalities : Aneuploidy topic in chapter Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Right answer is (B) Gynandromorph

To explain: In case of sexual mosaics there is loss in one of the sex chromosomes in some cells. In case of male there will thus be a mosaic of male and female parts CORRESPONDING to XY and XO DEPENDING on which part has which COMBINATION.

14.

Chromosome ____________ trisomy leads to Edward’s syndrome.(a) 12(b) 13(c) 18(d) 21This question was addressed to me during an interview.Origin of the question is Chromosomal Abnormalities : Aneuploidy topic in chapter Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Right answer is (C) 18

For explanation: Chromosome 18 TRISOMY will lead to EDWARD’s syndrome. Trisomy in chromosome 13 and 21 LEADS to Patau and Down’s syndrome RESPECTIVELY.

15.

Turner’s syndrome is a result of _________________(a) Nullisomy(b) Monosomy(c) Trisomy(d) PolysomyThis question was addressed to me in an interview for internship.I need to ask this question from Chromosomal Abnormalities : Aneuploidy in division Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Correct OPTION is (b) Monosomy

The explanation is: In Turner’s syndrome one set of sex chromosmome is LOST resulting in 44+XO FEMALES who have masculine condition. This is a RESULT of monosomy.

16.

In aneuploidy the entire set of chromosome is not involved in duplication of deletion.(a) True(b) FalseThis question was addressed to me during an online exam.This interesting question is from Chromosomal Abnormalities : Aneuploidy in section Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Correct choice is (a) True

Explanation: In aneuploidy the CHANGE is in one or TWO chromosomes and not an increase or decrease of an entire set. This MAKES it different from euploidy.

17.

Farmers often practice polyploidy as ____________________(a) It makes the plants more durable(b) They take longer time to undergo meiosis(c) It increases complexity and there is a hope of new species(d) It produces larger plant parts and productsThis question was addressed to me by my school teacher while I was bunking the class.My question comes from Chromosomal Abnormalities : Euploidy topic in division Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Right answer is (d) It PRODUCES larger plant PARTS and products

Easiest explanation: In case of polyploid, more is the number of chromosome set more is the amount of gene PRODUCT. As a result the plant will be larger is size which is a COMMERCIAL profit.

18.

Which of the following is not a possible cause of lethality of individuals carrying a deletion mutation?(a) Genes that are not haplo sufficient doesn’t produce adequate gene product(b) Genomic imbalance(c) Unmasking of lethal recessive alleles(d) Lack of diversityI had been asked this question by my school teacher while I was bunking the class.My question comes from Chromosomal Abnormalities : Deletion in section Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Correct option is (d) Lack of DIVERSITY

The explanation: With the other reasons being true, lack of diversity AFFECTS at POPULATION level not at INDIVIDUAL level. It is no cause for lethality of individuals with deleterious mutation.

19.

Tandem duplication creates ____________and reverse tandem creates_____________(a) Buckling, looping(b) Hairpin, buckling(c) Buckling, Hairpin(d) Loop with turn, hairpinI had been asked this question in my homework.Asked question is from Chromosomal Abnormalities : Duplication in portion Chromosomal Basis of Inheritance of Cytogenetics

Answer» RIGHT choice is (c) Buckling, HAIRPIN

Explanation: In case of tandem REPEAT the same sequence in same order is repeated. As parent chromosome has only ONE copy of that sequence the daughter bulges out. This, causes buckling. In reverse tandem the duplication is INVERTED in sequence which leads to formation of hairpin.
20.

There are two chromosomes 1- A—B—C—D—E and 2- F—G—H— I, if A—B—C and F—G undergo reciprocal translocation what will not be true?(a) New sequence at 1 will be C—D—E—F—G(b) The 1 will then pair with both 1’ and 2’(c) Pairing will be between same gene loci only(d) 2nd chromosome will become longerThis question was addressed to me during a job interview.I need to ask this question from Chromosomal Abnormalities : Translocation topic in portion Chromosomal Basis of Inheritance of Cytogenetics

Answer»

The CORRECT OPTION is (a) New sequence at 1 will be C—D—E—F—G

The best explanation: In reciprocal TRANSLOCATION, the PARTS are EXCHANGED between two chromosomes in same position. So, the new sequence of 1 should be F—G—C—D—E.

21.

Which of the following is not true about inversion?(a) Inverted chromosomes are generally viable(b) Inversion can cause chromosome breakage(c) Two DNA strands with an inverted segment will not pair(d) Inversion including centromere is known as paracenricThis question was addressed to me during an internship interview.This key question is from Chromosomal Abnormality : Inversion topic in chapter Chromosomal Basis of Inheritance of Cytogenetics

Answer»

The correct option is (C) Two DNA strands with an inverted segment will not pair

Best explanation: Two DNA segments in inversion will pair but the pairing will be via FORMATION of a LOOP such that appropriate GENE loci can come close. Other options about inversion are TRUE.

22.

Consider this sequence A—O—B —C—D—E—F, be a DNA sequence where O is the centromere. Which of the following will be a pericentric inversion?(a) A—O—B—D—E—F(b) B—O—A—D—E—F(c) D—B—O—A—E—F(d) A—O—E—D—B—FI have been asked this question in my homework.This intriguing question comes from Chromosomal Abnormality : Inversion topic in division Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Right choice is (d) A—O—E—D—B—F

Easy explanation: PERICENTRIC inversion is the inversion that doesn’t involve the CENTROMERE. Here in OPTION A there is no change at all, option B and C are including the centromere. Only option D doesn’t involve the centromere in the inverted SEQUENCE, so it is pericentric.

23.

____________ is mandatory for autonomous transposition.(a) Internal gene(b) Transposase(c) 3’ concensus of region upstream to transposition(d) Branch point AThis question was posed to me in an interview for job.This question is from Chromosomal Abnormalities : Translocation topic in chapter Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Correct choice is (b) Transposase

For explanation: RECOMBINASE such as transposase or integrase is mandatory for transposition as they HELP in RECOMBINATION at TERMINAL repeats. Branch poit A is needed in SPLICING and internal gene is not mandatory.

24.

Choose the odd one out?(a) Leaf(b) Endosperm(c) Fertilized egg(d) PetalsThis question was addressed to me during an internship interview.The query is from Chromosomal Abnormalities : Euploidy in portion Chromosomal Basis of Inheritance of Cytogenetics

Answer»

The correct choice is (B) Endosperm

The best EXPLANATION: MAKING a distinction on the BASIS of a number of sets of chromosome- endosperm is TRIPLOID while the rest are diploid.

25.

In drosophila male there is no cross over suppression due to pericentric inversion as___________(a) They have only one set of chromosome(b) They always have double cross over(c) They never recombine(d) They don’t undergo meiosisThis question was posed to me by my college director while I was bunking the class.Question is taken from Chromosomal Abnormality : Inversion topic in division Chromosomal Basis of Inheritance of Cytogenetics

Answer» CORRECT option is (c) They never recombine

To explain: Drosophila males don’t recombine due to the ABSENCE of synaptonemal COMPLEX formation. THUS there is no question of recombination for it to be suppressed.
26.

Which of the following is not true about the Notch gene in Drosophila?(a) It causes a special indentation of the wing margin(b) It is expressed in heterozygous form(c) Notch is lethal in homozygous form(d) Notch is recessive to FacetThis question was addressed to me during an online interview.My question is taken from Chromosomal Abnormalities : Deletion topic in chapter Chromosomal Basis of Inheritance of Cytogenetics

Answer»

The correct OPTION is (d) Notch is recessive to FACET

For explanation I would SAY: Facet is expressed only in absence of Notch gene by deletion, thus it is pseudo dominant and recessive to the notch gene. Other options are TRUE, notch is also LETHAL in hemizygous condition.

27.

What are the results of pericentric inversion with single crossing over?(a) Two normal, one dicentric and one acentric chromosome(b) 2 dicentric and 2 acentric chromosomes(c) Four normal chromosomes with centriomere in different positions(d) 3 normal chromosome, one abnormal acentric chromosomeI had been asked this question in an internship interview.My question is from Chromosomal Abnormality : Inversion topic in portion Chromosomal Basis of Inheritance of Cytogenetics

Answer»

The correct option is (a) Two normal, one dicentric and one acentric CHROMOSOME

The EXPLANATION: RECOMBINATION in the paracentric region will take place between only two STRANDS, so the other two strands will be normal. This recombination will RESULT in one dicentric chromosome and another acentric chromosome.

28.

If a part of the chromosome was transferred to a non-homologous chromosome say 1 to 1’. Then which of the following is not true?(a) The pairing in meiosis will be affected(b) The chromosome will be torn apart while segregation(c) In most of the cases, the resultant gamete will be non-viable(d) The pairing will be between 4 homologous chromosomesThis question was addressed to me in my homework.The question is from Chromosomal Abnormalities : Translocation topic in division Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Correct option is (b) The chromosome will be torn apart while segregation

To explain: The CHROMOSOMES will not join as in CASE of inversion, so the chromosome will not SNAP at the anaphase. But the distribution of the gene will be UNEQUAL.

29.

In animals polypoidy is rarely practiced as _______________(a) Giants are harder to train and take care of(b) Increase in size is not appreciable(c) It is often sterile(d) Animal cells are resistant to colchicineThis question was addressed to me in quiz.Query is from Chromosomal Abnormalities : Euploidy in portion Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Correct choice is (b) INCREASE in size is not appreciable

For explanation I would say: The other options being true, in animals there is a more strict regulation of GENE PRODUCT formation than in the CASE of PLANTS. In animals with an increase in cell size there would be a decrease in cell number keeping the ultimate animal sizes same. It is thus not profitable at all.

30.

You generate a fluorescent probe against a gene that has been deleted. You expose the DNA to the probe and observe it under fluorescent microscope. What will you see?(a) Fluorescence will correspond to the gene of interest(b) There will be a number of regions that emit fluorescence(c) Most parts of the chromosome emits fluorescence(d) Nothing is seen under fluorescence microscopeI had been asked this question in semester exam.This is a very interesting question from Chromosomal Abnormalities : Deletion topic in division Chromosomal Basis of Inheritance of Cytogenetics

Answer» RIGHT answer is (d) Nothing is seen under fluorescence microscope

Easiest explanation: The gene CORRESPONDING to the probe labeled with fluorescence is deleted. Thus, probe can’t BIND the DNA. In this CASE no fluorescence should be seen on the chromosome.
31.

If a gene undergoes duplication and one of the duplicated copy is mutated to render unexpressed protein. What will be the effect on phenotype?(a) Mutant phenotype(b) Normal phenotype(c) Expression of the mutant gene is less than that would occur if both copy active(d) The gene not expressed at allThe question was asked in an international level competition.The query is from Chromosomal Abnormalities : Duplication in portion Chromosomal Basis of Inheritance of Cytogenetics

Answer»

The correct ANSWER is (b) Normal phenotype

The best I can explain: In this case as the product of the 2^nd copy is mutated and not AFFECTING the phenotype, only one copy is producing the required product in normal quantity. This is SIMILAR to the DUPLICATION being silenced.

32.

Which of the following could be due to duplication?(a) Co-dominance(b) Dominance(c) Incomplete dominance(d) PleiotropyThis question was addressed to me by my school teacher while I was bunking the class.This intriguing question originated from Chromosomal Abnormalities : Duplication topic in division Chromosomal Basis of Inheritance of Cytogenetics

Answer»

The correct option is (d) Pleiotropy

The best I can explain: In case of Pleiotropy one gene effects SEVERAL CHARACTER; this may be due to mutations of the initial DUPLICATED SEQUENCES.

33.

In pericentric inversion, the inversion loop involves __________ strands.(a) 1(b) 2(c) 3(d) 4The question was asked at a job interview.My doubt stems from Chromosomal Abnormality : Inversion in portion Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Right option is (d) 4

The best I can EXPLAIN: In PERICENTRIC INVERSION there will be 4 strands in the inversion LOOP although only 2 will undergo recombination to give the recombination products. This is because the sister chromatids are bound by the centromere.

34.

You observe a genetic trait which is a common occurrence in the male of a particular pedigree, this is possibly a ______________(a) X linked(b) Y linked(c) X linked recessive(d) Y linked dominantI got this question by my school teacher while I was bunking the class.I want to ask this question from Chromosomal Theory of Inheritance topic in portion Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Right answer is (b) Y linked

Best explanation: If the gene has a sex bias it is CERTAINLY sex linked. In this CASE, it is a common OCCURANCE in the MALES only in a pedigree so it must be Y linked gene. There is no dominant recessive as Y is always hemizygous.

35.

Which human chromosomes are involved in Down’s syndrome?(a) 6(b) 14 and 21(c) 8 and 12(d) X and YI had been asked this question in class test.Question is taken from Chromosomal Abnormalities : Duplication topic in section Chromosomal Basis of Inheritance of Cytogenetics

Answer»

The CORRECT answer is (b) 14 and 21

The best explanation: In Down’s SYNDROME a part of the 21^st chromosome’s long ARM duplicates and TRANSFERS to chromosome 14’s long arm.

36.

The probability of aneuploidy in offspring increases with age as _________________(a) Chromosomes tend to lose information with age(b) Pairings at dichtyotene stages are gradually lost(c) Ability of fertilization with age is gradually lost(d) Chromosomal aberration with ageI had been asked this question in class test.My question comes from Chromosomal Abnormalities : Aneuploidy topic in section Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Correct choice is (b) PAIRINGS at dichtyotene stages are gradually lost

The explanation: The CHROMOSOMES with AGE tend to lose the proper pairings that existed when they were in dictyotene stage as this is PROLONGED over decades. This LEADS to improper segregation causing trisomy.

37.

If the XIC passes to chromosome 3 in a human what will be the result?(a) Chromosome 3 will have one more protein to express(b) Human race will divide into two species(c) Chromosome 3 will be inactivated(d) There will be sticking of chromosome 3 with other chromosomesI had been asked this question in semester exam.Question is taken from Chromosomal Abnormalities : Translocation in chapter Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Correct option is (c) Chromosome 3 will be inactivated

For explanation: XIC is responsible for SILENCING one of the X chromosomes in a female for dosage compensation. If an XIC is PRESENT within the chromosome 3 it will be considered SIMILAR to an X chromosome and it MAY as well be inactivated.

38.

Which of the following is not a type of translocation?(a) Simple(b) Reciprocal(c) Tandem(d) IntercalaryThis question was addressed to me by my school teacher while I was bunking the class.This intriguing question comes from Chromosomal Abnormalities : Translocation topic in portion Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Right option is (c) TANDEM

The explanation is: Simple translocation is the transfer of a BROKEN piece of one chromosome to the END of another. Reciprocal is the exchange of parts between the two chromosomes intercalary is translocation to an INTERMEDIATE LOCATION. There is no tandem translocation.

39.

A male bee can’t have a________________(a) Mother(b) Faher(c) Grand father(d) Grand motherI had been asked this question in an internship interview.This interesting question is from Chromosomal Abnormalities : Euploidy in section Chromosomal Basis of Inheritance of Cytogenetics

Answer»

The CORRECT OPTION is (c) Grand father

Explanation: A male BEE is produced from the unfertilized EGGS by parthenogenesis, thus it will have a mother but not a father. The female mother was produced by FERTILIZATION so there is a grandfather and grandmother.

40.

In translocating gene fragment which part is responsible for translocation?(a) The LTR(b) The transcribed gene(c) The non-coding part of gene(d) The surrounding sequencesI got this question in an online interview.I want to ask this question from Chromosomal Abnormalities : Translocation in section Chromosomal Basis of Inheritance of Cytogenetics

Answer»

The correct ANSWER is (a) The LTR

To EXPLAIN: The long terminal repeats or LTR is present in both ends of TRANSLOCATING regions which are responsible for RECOMBINATION.

41.

If you cross a red eyed pure breeding female Drosophila with a white eyed male, then the F1 males so produces were crossed with white eyed male, what will be the eye colour of their daughters and sons in F2?(a) Both daughters and sons red eyed(b) Daughters with both eye colour while sons with white eye(c) Both daughters and sons with both eye colours(d) Daughters with red eye and sons with white eyesI have been asked this question in an interview.Enquiry is from Chromosomal Theory of Inheritance in section Chromosomal Basis of Inheritance of Cytogenetics

Answer»

The correct choice is (d) Daughters with red eye and sons with white eyes

To elaborate: Eye colour is a sex linked trait. In this following case, the F1 male PROGENY was red eyed, as the father only gave the Y chromosome and not X which DETERMINES eye colour. Then similarly the F2 sons would be white eyed by allele from their mother, female will be red eyed as they GET both ALLELS.

42.

Which of the following is an example of trisomy ________________(a) Endosperm(b) Klinefelter(c) Turner(d) XerodermaThis question was addressed to me in an online interview.This intriguing question comes from Chromosomal Abnormalities : Aneuploidy topic in division Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Right answer is (b) Klinefelter

To explain I would say: Klinefelter syndrome results from trisomy in sex chromosome PRODUCING 44+ XXY. Turner is due to MONOSOMY, ENDOSPERM is triploid i.e. the complete set of chromosome is increased and XP is due to mutation or deletion in gene not entire chromosome.

43.

Euploidy is a form of allopoliplody.(a) True(b) FalseThis question was posed to me in an interview.This interesting question is from Chromosomal Abnormalities : Euploidy topic in section Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Correct ANSWER is (b) False

The explanation is: In euploidy there is an INCREASE in chromosomal SET due to duplication of originally existing set and not due to blending of chromosomes of TWO organisms. Thus it is AUTOPLOIDY and not Alloploidy.

44.

The appearance of a recessive phenotype due to deletion of dominant gene is called_______________(a) Hemi-dominance(b) Pseudo dominance(c) Imperfect dominance(d) Co-dominanceI have been asked this question during an online interview.This interesting question is from Chromosomal Abnormalities : Deletion in section Chromosomal Basis of Inheritance of Cytogenetics

Answer»

The correct CHOICE is (b) Pseudo DOMINANCE

For explanation: Pseudo dominance is the condition when the recessive allele is expressed in deletion mutation of dominant. Hemi-dominance is the condition when only one COPY of the gene is supposed to be PRESENT, as in genes of Y chromosomes. Co-dominance and imperfect dominance are different.

45.

Which of the following is not seen in cut-paste transposition, but seen in copy-paste method?(a) Synaptic complex(b) Strand transfer(c) Transposase(d) ResolvaseThe question was posed to me in an internship interview.The above asked question is from Chromosomal Abnormalities : Translocation topic in portion Chromosomal Basis of Inheritance of Cytogenetics

Answer» CORRECT answer is (d) Resolvase

For EXPLANATION I would say: In addition to what is required in cut-paste mechanism, replicative transposition also REQUIRES enzyme resolvase to RESOLVE the structure FORMED after strand transfer reaction.
46.

If a gamete has 16 chromosomes, what will be the number of chromatids before anaphase 1?(a) 8(b) 16(c) 32(d) 64I got this question during an interview for a job.This interesting question is from Chromosomal Theory of Inheritance topic in section Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Correct option is (d) 64

Easiest explanation: There are 32 chromosomes but they are in duplicate chromatids so 64 is the number of chromatids before anaphase 1.

47.

Which of the following pairing will not occur during meiosis of tetraploid?(a) Two bivalent(b) One bivalent and two univalent(c) Trivalent and univalent(d) QuadrivalentThe question was asked in a national level competition.The question is from Chromosomal Abnormalities : Euploidy in division Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Correct option is (b) One bivalent and two UNIVALENT

For EXPLANATION I would say: In normal pairing all available chromosomes with complimentary are paired, so the existence of two univalent which are free to pair is not possible. HOWEVER in case of trivalent and univalent as one of the other SET is not available univalent exists.

48.

Yellow colour of mouse is generated by _________ mutation.(a) Duplication(b) Deletion(c) Inversion(d) TranslocationThis question was posed to me at a job interview.I want to ask this question from Chromosomal Abnormalities : Deletion in portion Chromosomal Basis of Inheritance of Cytogenetics

Answer»

Correct choice is (B) Deletion

For explanation I would say: Here the agouti allele which is to be EXPRESSED only in certain tissues is brought under the control of RALLY gene promoter which is expressed in all tissues, by deletion of Rally gene and agouti promoter in between the TWO. The strong promoter over expresses Agouty gene leading to the COLOR.

49.

Deletion of a region led to over expression of a gene X. What do you conclude from this observation?(a) Part of gene X is mutated(b) Promoter of gene X is deleted(c) Regulator of gene X is deleted(d) No effect on gene X or its regulatorsI have been asked this question in an international level competition.Question is from Chromosomal Abnormalities : Deletion topic in chapter Chromosomal Basis of Inheritance of Cytogenetics

Answer»

The correct choice is (c) Regulator of gene X is deleted

Explanation: In this case over EXPRESSION of gene X is due to deletion of some negative regulator like OPERON, insulator, silencer ETC.

50.

What will be the effect of the deletion mutation of a gene at the telomere?(a) Organism will dye(b) Organism will develop serious hazards due to absence of the gene and its product(c) Mild effect on the phenotype(d) No effectI had been asked this question during an internship interview.This intriguing question originated from Chromosomal Abnormalities : Deletion topic in section Chromosomal Basis of Inheritance of Cytogenetics

Answer» RIGHT choice is (d) No effect

Easy explanation: The GENES at the TELOMERE are silenced, and never expressed. It is in form of heterochromatin inaccessible to the transcription machinery. Thus, deletion of a gene that wasn’t expressed to start with doesn’t make MUCH difference.