1.

Consider a series RLC circuit having resistance = 1Ω, capacitance = 1 F, considering that the capacitor gets charged to 10 V. At t = 0 the switch is closed so that i = e^-2t. When i = 0.37 A, the voltage across capacitor is _____________(a) 1 V(b) 6.7 V(c) 0.37 V(d) 0.185 VThis question was addressed to me by my college professor while I was bunking the class.My question is from Advanced Problems Involving Complex Circuit Diagram in division Network Theory and Complex Circuit Diagram of Network Theory

Answer»

The correct choice is (B) 6.7 V

To explain I would say: We know that, during DISCHARGE of capacitor,

VC = VR

Now, VR = 0.67 X 10 = 6.7 V

So, VC= 6.7 V.



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