1.

Consider the figure and answer the following questions. (i) Identify the graphed function.(ii) Discuss the continuity of the above function at x = 2.

Answer»

(i) (b) f(x) = \(\begin{cases} \frac{|x-2|}{x-2}, & \quad x≠2\\ 0, & \quad x=2 \end{cases} \)

(ii) From the figure we can see that
f(2) = 1, f(2+) = -1 and f(2) = 0
Therefore, f(2) = 1 ≠ f(2+) = -1 ≠ f(2) = 0. Discontinuous.



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