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Consider the system of equations ` log_(3)(log_(2)x)+log_(1//3)(log_(1//2)y) =1 and xy^(2) = 9`. The value of 1/y lies in the intervalA. `(5, 7)`B. `(7, 10)`C. `(11, 15)`D. `(25, 30)` |
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Answer» Correct Answer - B `log_(3)(log_(2)x)+log_(1//3)(log_(1//2)y) = 1` ` rArr log_(3) (log_(2)x)-log_(3)(-log_(2)y) = 1` ` rArr log_(3)(-(log_(2)x)/(log_(2)y)) = 1` ` rArr -(log_(2)x)/(log_(2)y) = 3` ` rArr xy^(3) = 1` Also, ` xy^(2) = 9` ` rArr y = 1/9` ` :. x = 729` |
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