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(Cos^3theta-sin^3theta/costheta-sintheta)-(cos^3theta+sin^3theta/costheta+sintheta)=1 |
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Answer» Not able to understand complrtely.. Use the identity (a^3+b^3)= (a+b)(a^2+b^2-ab)sin^3A + cos^3A÷(sinA +cos ). + sinA.cosA(sinA+cosA)(sin^2+cos^2 -sinA.cosA)÷ (sinA + cosA)+ sinA.cosAor( sinA^2+cosA^2 -sinA.cosA) +sinA.cosA1-sinA.cosA+sinA.cosA1 |
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