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Cos 45 /sec 30 + cosec 30 please explain me how to do this???? |
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Answer» {tex}\\begin{array}{l}\\frac{\\cos45}{sec30}+\\cos ec30\\\\=\\frac{\\displaystyle\\frac1{\\sqrt2}}{\\displaystyle\\frac2{\\sqrt3}}+2=\\frac1{\\sqrt2}\\times\\frac{\\sqrt3}2+2\\\\=\\frac{\\sqrt3}{2\\sqrt2}+2\\\\=\\frac{\\sqrt3{\\displaystyle+}{\\displaystyle4}{\\displaystyle\\sqrt2}}{2\\sqrt2}=\\frac{1.73+4\\times1.41}{2\\times1.41}=\\frac{1.73+5.64}{2.82}\\\\=\\frac{7.37}{2.82}=2.613\\\\\\end{array}{/tex} I had puteen thia value but i m not able to solve please explain it Hope it will help you Just put the values and then solve, cos 45= 1/root2 , sec 30= 2/root3, and cosec 30=2. |
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