cos 75° – cos 15° =___________________(a) \(\frac{\sqrt{3}}{\sqrt{2}}\)(b) \(\frac{\sqrt{2}}{\sqrt{3}}\)(c) \(\frac{1}{\sqrt{2}}\)(d) –\(\frac{1}{\sqrt{2}}\)The question was asked in unit test.Enquiry is from Trigonometric Functions of Sum and Difference of Two Angles-2 in division Trigonometric Functions of Mathematics – Class 11

cos 75° – cos 15° =___________________(a) \(\frac{\sqrt{3}}{\sqrt{

1.	cos 75° – cos 15° =___________________(a) \(\frac{\sqrt{3}}{\sqrt{2}}\)(b) \(\frac{\sqrt{2}}{\sqrt{3}}\)(c) \(\frac{1}{\sqrt{2}}\)(d) –\(\frac{1}{\sqrt{2}}\)The question was asked in unit test.Enquiry is from Trigonometric Functions of Sum and Difference of Two Angles-2 in division Trigonometric Functions of Mathematics – Class 11
Answer» RIGHT choice is (d) –\(\frac{1}{\SQRT{2}}\) The EXPLANATION: cos X – cos y = – 2 sin (x+y)/2 sin (x-y)/2 cos 75° – cos 15° = – 2 sin (75°+15°)/2sin(75°-15°)/2 = – 2 sin 45° sin 30° = – 21/\(\sqrt{2}\)1/2= – 1/\(\sqrt{2}\).

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