If sec x = 13/5 and x lies in 4^th quadrant, then find cot x.(a) 5/12(b) -5/12(c) 5/13(d) -5/13I had been asked this question in examination.This is a very interesting question from Trigonometric Functions in portion Trigonometric Functions of Mathematics – Class 11

If sec x = 13/5 and x lies in 4^th quadrant, then find cot x.(a) 5/12(

1.	If sec x = 13/5 and x lies in 4^th quadrant, then find cot x.(a) 5/12(b) -5/12(c) 5/13(d) -5/13I had been asked this question in examination.This is a very interesting question from Trigonometric Functions in portion Trigonometric Functions of Mathematics – Class 11
Answer» Right OPTION is (b) -5/12 To elaborate: SEC x = 13/5. We KNOW, sec^2x – tan^2x=1 tan^2x = (13/5)^2-1 = (169/25) – 1 = 144/25 tan x = ±12/5 tan x is negative in 4^th quadrant so, tan x=-12/5 cot x = 1/tan x = 1/(-12/5) = – 5/12.

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If sec x = 13/5 and x lies in 4^th quadrant, then find cot x.(a) 5/12(b) -5/12(c) 5/13(d) -5/13I had been asked this question in examination.This is a very interesting question from Trigonometric Functions in portion Trigonometric Functions of Mathematics – Class 11

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