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Find cos 2x if cos x = 1/\(\sqrt{2}\).(a) 1/2(b) 0(c) \(\sqrt{3}\)/2(d) 1The question was posed to me during an interview.My question comes from Trigonometric Functions of Sum and Difference of Two Angles-1 topic in chapter Trigonometric Functions of Mathematics – Class 11

Answer»

Correct answer is (b) 0

Easy explanation: We KNOW, COS 2x = cos^2x – sin^2x = 2cos^2x – 1 {sin^2x = 1-cos^2x}

= 2(1/\(\sqrt{2}\))^2-1 = 2(1/2) – 1 = 1-1 = 0.



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