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If tan x=1/\(\sqrt{3}\), then sin 2x =___________________(a) 1/\(\sqrt{2}\)(b) 1/2(c) \(\sqrt{3}\)/2(d) 1I got this question during an online interview.My doubt is from Trigonometric Functions of Sum and Difference of Two Angles-2 in chapter Trigonometric Functions of Mathematics – Class 11

Answer»

Correct OPTION is (C) \(\SQRT{3}\)/2

For explanation I WOULD say: We know, sin 2x = (2 tan x) / (1 + tan^2x)

sin 2x=(2*1/\(\sqrt{3}\)) / (1+1/3) = (2*3)/4*\(\sqrt{3}\) = \(\sqrt{3}\)/2.



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