cos 75° + cos 15° =___________________(a) \(\frac{\sqrt{3}}{\sqrt{2}}\)(b) \(\frac{\sqrt{2}}{\sqrt{3}}\)(c) \(\frac{\sqrt{3}}{2}\)(d) \(\frac{1}{\sqrt{2}}\)The question was asked in a job interview.The question is from Trigonometric Functions of Sum and Difference of Two Angles-2 in chapter Trigonometric Functions of Mathematics – Class 11

cos 75° + cos 15° =___________________(a) \(\frac{\sqrt{3}}{\sqrt{2}

1.	cos 75° + cos 15° =___________________(a) \(\frac{\sqrt{3}}{\sqrt{2}}\)(b) \(\frac{\sqrt{2}}{\sqrt{3}}\)(c) \(\frac{\sqrt{3}}{2}\)(d) \(\frac{1}{\sqrt{2}}\)The question was asked in a job interview.The question is from Trigonometric Functions of Sum and Difference of Two Angles-2 in chapter Trigonometric Functions of Mathematics – Class 11
Answer» CORRECT choice is (a) \(\frac{\sqrt{3}}{\sqrt{2}}\) Explanation: We KNOW, cos x + cos y = 2 cos (x+y)/2 cos (x-y)/2 cos 75° + cos 15° = 2 cos (75°+15°)/2 cos(75°-15°)/2 = 2 * cos 45° * cos30° = 2(1/\(\sqrt{2}\))(\(\sqrt{3}\)/2) = \(\sqrt{3}\)/\(\sqrt{2}\).

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