Cos(90-x)sec x tan(90- x)/sin^2(90- x) sec+90-x)

1.	Cos(90-x)sec x tan(90- x)/sin^2(90- x) sec+90-x)
Answer» 1/cos^4 Sorry, can u type the question again clearly. Coz i am not sure where does the bracket open but closes at the end

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