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Cos thita equals to |
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Answer» Cos θ = (Adjacent side)/(Hypotenuse side) = √(1-sin^2 θ) = 1/(sec θ) = sin(90-θ) = sin((π/2)-θ) = sin(90+θ) = sin((π/2)+θ) = (sin 2θ)/(2 cos θ) = √(1+cos 2θ)/2 = (tan θ)/(sin θ) = (cos θ)/(cot θ) 1/sin thita 1/sec thita, |
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