1.

Cos thita equals to

Answer» Cos θ = (Adjacent side)/(Hypotenuse side) = √(1-sin^2 θ) = 1/(sec θ) = sin(90-θ) = sin((π/2)-θ) = sin(90+θ) = sin((π/2)+θ) = (sin 2θ)/(2 cos θ) = √(1+cos 2θ)/2 = (tan θ)/(sin θ) = (cos θ)/(cot θ)
1/sin thita
1/sec thita,


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