InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
(cos0°+sin45°+sin30°)(sin90°-cos45°+cos60°). Plz give the answer.....plz |
| Answer» We know that, cos0°=1 =sin90°, sin45°=(1/√2)= cos45° & sin30°=(1/2)=cos60°, putting these values in the given expression, we get:-{tex}\\left( {\\cos 0^\\circ +\\sin 45^\\circ +\\sin 30^\\circ }\\right)\\left( {\\sin 90^\\circ -\\cos 45^\\circ +\\cos 60^\\circ } \\right){/tex}{tex} = \\left( {1 + \\frac{1}{{\\sqrt 2 }} + \\frac{1}{2}} \\right)\\left( {1 - \\frac{1}{{\\sqrt 2 }} + \\frac{1}{2}} \\right){/tex}{tex} = \\left( {\\frac{{2\\sqrt 2 + 2 + \\sqrt 2 }}{{2\\sqrt 2 }}} \\right)\\left( {\\frac{{2\\sqrt 2 - 2 + \\sqrt 2 }}{{2\\sqrt 2 }}} \\right){/tex}{tex} = \\left( {\\frac{{3\\sqrt 2 + 2}}{{2\\sqrt 2 }}} \\right)\\left( {\\frac{{3\\sqrt 2 - 2}}{{2\\sqrt 2 }}} \\right){/tex}{tex} = \\frac{{{{\\left( {3\\sqrt 2 } \\right)}^2} - {{\\left( 2 \\right)}^2}}}{8}{/tex}\xa0[Identity (a + b)(a - b) = a2 - b2]{tex} = \\frac{{18 - 4}}{8}{/tex}{tex} = \\frac{{14}}{8} = \\frac{7}{4}{/tex} | |