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cos38° cos52° - sin38° sin52° =0 |
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Answer» Yes answer is zero Ncert solution m h 1/1+sin square A+1/1+cos squareA+1/1+sec square A+1/1+cos square A=2 RHS Cos 38* cos 52* --- sin 38* sin 52*Cos(90-52) cos (90-38) - sin 38* - sin52*Sin 52* × sin38* - sin 38 * - sin 52* = 0 therefore, LHS=RHS=0 hum ques ko iss form me likh skte h....becoz of identity that sin theta= cos(90°-theta)....sin52°sin38°-sin38°sin52°=0 |
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