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| 1. |
CosA/1-tanA+sinA/1-cotA=sinA+cosA |
| Answer» LHS=cosA/(1-tanA)+sinA/(1-cotA)=cos\xa0A/(1 - sin\xa0A/cos A) + sin A/(1 - cos A/sin A)=cos²A/ (cos A - sin A) + sin²A / (sin A - cos A)=cos²A/ (cos A - sin A) - sin²A / (cos A - sin A)=(cos ² A - sin ² A) / (cos A - sin A)=(cos A - sin A)(cos A + sin A) / (cos A - sin A)=cos A + sin A i.e RHSRead more on Brainly.in - https://brainly.in/question/1346932#readmore | |