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CosA - 2/5 then find 4+ 4tan square A |
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Answer» Let, CosA-2/5 =0 CosA =2/5 b/hNow A to Q Using pthogreus theroemP² =H² -B²P²= 25 - 4P = √21Now, 4+ 4(√21/2)² (> tan = P/H ) 4+21 25 4 + 4tan^2 A =4( 1+tan ^2 A) =4× sec ^2 A =4 × 1÷cos ^2 A =4× (25÷4 ) =25 Sorry...its 25 13 |
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