InterviewSolution
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InterviewSolution
| 1. |
cosA-sinA+1/cosA+sinA-1=cosecA-cotA |
| Answer» LHSDIVIDE NUMERATOR AND DENOMINATOR BOTH BY sin A =(CosA÷sinA - sinA÷sinA +1÷sinA)/(cosA÷sinA + sinA÷sinA - 1÷sinA)=(CotA-1+cosecA)/(cotA+1-cosecA)At the place of 1 at the numerator write (cosec2A -cot2A)={CotA+cosecA-(cosec2A-cot2A)}/(cotA-cosecA+1)={CotA+cosecA-(cosecA+cotA)(cosecA-cotA)}/(cotA-cosecA+1)=(CotA+cosecA){1-(cosecA-cotA)}/(cotA-cosecA+1)={(cotA+cosecA)(1-cosecA+cotA)}/(cotA-cosecA+1)=CotA+cosecAHENCE PROVEDLHS=RHS | |