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| 1. |
Cosec^3 30× cos60×tan^45×sin^90×sec^40×cot30 |
| Answer» We know that, cosec30°=2, cos60°=(1/2), tan45°=1=sin90°, sec45°=√2 & cot30°=√3,putting these values in the given expression, we get:-{tex}\\cos e{c^3}30^\\circ \\cos 60^\\circ {\\tan ^3}45^\\circ {\\sin ^2}90^\\circ {\\sec ^2}45^\\circ \\cot 30^\\circ {/tex}{tex} = {(2)^3} \\times {\\left( {\\frac{1}{2}} \\right)} \\times {(1)^3} \\times {(1)^2} \\times {\\left( {\\sqrt 2 } \\right)^2} \\times \\sqrt 3 {/tex}{tex} = 8 \\times \\frac{1}{2} \\times 1 \\times 1 \\times 2 \\times \\sqrt 3 {/tex}{tex} = 8\\sqrt 3 {/tex} | |