Cosec2 63°+tan2 24°/cot2 66° +Sec2 63°+cos63°sin27°+sin 27° sec63°/2 (cosec2 65°_tan2 25°)

Cosec2 63°+tan2 24°/cot2 66° +Sec2 63°+cos63°sin27°+sin 27° sec

1.	Cosec2 63°+tan2 24°/cot2 66° +Sec2 63°+cos63°sin27°+sin 27° sec63°/2 (cosec2 65°_tan2 25°)
Answer» 1 + tan2\xa00\xa0= sec2\xa00\xa0{tex}x = {-b \\pm \\sqrt{b^2-4ac} \\over 2a}{/tex}\u200b\u200b\u200b\u200b\u200b Sec2 (90-24) +tan2 24/tan2 (90-24)+Sec2 27Sin2 63+cos 63.cos (90-63)+sin 27. Cosec 27/2 (Cosec2 65-cot2 65)Sec2 24+ tan2 24/tan2 24+Sec2 27+Sin2 63+cos2 63 + SIN 27. COSEC 27/2×11+1+1/2=2/2=11+1=2 Ans.