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| 1. |
(cosecA -sinA)(secA-cosA)=1/tanA+cotA |
| Answer» LHS: (1/sinA-sinA) (1/cosA-cosA) (1-sin sq A/sinA)(1-cos sq A/cosA) ( cos sq A/sinA)( sin sq A/cosA) = cosAsinARHS: 1/sinA/cosA+cosA/sinA Sin sq A + cos sq A/sinAcosA 1/1/sinAcosA = sinAcosA LHS =RHS HENCE PROVED | |