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cot 15° =______________(a) 2+\(\sqrt{3}\)(b) 2-\(\sqrt{3}\)(c) 1+\(\sqrt{3}\)(d) \(\sqrt{3}\)-1I have been asked this question during an interview for a job.My enquiry is from Trigonometric Functions of Sum and Difference of Two Angles-1 topic in portion Trigonometric Functions of Mathematics – Class 11

Answer»

Correct option is (a) 2+\(\SQRT{3}\)

The explanation: We KNOW, cot (X – y) = (cot x cot y +1)/cot y – cot x)

cot(45°-30°) = (cot 45° cot 30°+1)/(cot 45° – cot 30°)

cot 15° = (\(\sqrt{3}\) + 1)/(\(\sqrt{3}\) – 1) = 2+\(\sqrt{3}\).



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