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| 1. |
Cot A + tan B ÷ cot B + tan A = cot A tan B |
| Answer» {tex}\\frac { cotA+tanB }{ cotB+tanA } =\\frac { \\frac { 1 }{ tanA } +tanB }{ \\frac { 1 }{ tanB } +tanA } =\\frac { \\frac { 1+tanB.tanA }{ tanA } }{ \\frac { 1+tanA.tanB }{ tanB } } \\quad \\quad \\quad \\quad \\left[ \\frac { 1 }{ tan\\theta } =cot\\theta \\right] \\quad \\\\ =\\frac { 1+tanB.tanA }{ tanA } .\\frac { tanB }{ 1+tanA.tanB } =\\frac { tanB }{ tanA } =tanB.\\frac { 1 }{ tanA } =cotA.tanB{/tex} | |