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Cot54degree/tan 36degree+tan20degree/cot70gegree-2 |
| Answer» Q.\xa0{tex}\\huge {\\frac{\\cot\\ 54^\\circ}{\\tan\\ 36^\\circ}+\\frac{\\tan\\ 20^\\circ}{\\cot\\ 70^\\circ} -2=?}\\\\{/tex}Sol:\xa0\t{tex}\\huge {=> \\ \\frac{\\cot\\ 54^\\circ}{\\tan\\ 36^\\circ}+\\frac{\\tan\\ 20^\\circ}{\\cot\\ 70^\\circ} -2}\\\\.\\\\\\huge {=> \\ \\frac{\\tan\\ 36^\\circ}{\\tan\\ 36^\\circ}+\\frac{\\tan\\ 20^\\circ}{\\tan\\ 20^\\circ} -2}\\\\.\\\\\\huge {=> \\ 1+1 -2}\\\\.\\\\\\huge {=> 0}\\\\.\\\\{/tex}{tex}\\Large {\\Bigg( {\\because\\ \\cot \\ \\theta=\\tan\\ (90^\\circ-\\theta)\\\\\\therefore \\cot\\ 54^\\circ=\\tan\\ (90^\\circ-54^\\circ)=\\tan\\ 36^\\circ\\\\and,\\ \\cot\\ 70^\\circ=\\tan\\ (90^\\circ-70^\\circ)=\\tan\\ 20^\\circ\\Bigg)\\\\}}{/tex}\t\xa0 | |