D is a point on the side BC of a triangle ABC suct that angle ADC=angle BAC. Show that CA2=CB.CD

D is a point on the side BC of a triangle ABC suct that angle ADC=angl

1.	D is a point on the side BC of a triangle ABC suct that angle ADC=angle BAC. Show that CA2=CB.CD
Answer» ∆ADC and ∆BACAngle ADC=angle BACAngle C =angle CHence ∆ADC~∆BACCA/CD=CB/CAHence CA2=CB.CDProved