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`Delta= |{:(1,,1+ac,,1+bc),(1,,1+ad,,1+bd),(1,,1+ae,,1+be):}|` is independent ofA. aB. bC. c,d,eD. none of these |
Answer» Correct Answer - A::B::C Operating `C_(2) to C_(2)-C_(1),C_(3) to C_(3)-C_(1)` we get `Delta =|{:(1,,ac,,bc),(1,,ad,,bd),(1,,ae,,be):}|=ab|{:(1,,c,,c),(1,,d,,d),(1,,e,,e):}|= ab (0) =0` |
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